我爱小程序
求救
wx.request请求自己的后台接口地址，发现不是ajax请求了。变成了普通请求
本来我后台接口地址是 https://api.xxx.com
但是wx.request确ajax请求了
Request URL:
https://open.weixin.qq.com/connect/oauth2/authorize?appid=wxe32c5c4c00b81230&redirect_uri=http://api.xxxx.com/index.php?route=account/register&response_type=code&scope=snsapi_base&state=STATE
Request Method:
GET
Status Code:
301 Moved Permanently
Remote Address:
180.163.15.222:443
Referrer Policy:
no-referrer-when-downgrade
然后这个页面返回的内容是
<!DOCTYPE html>
<html>
<head>
<meta name="viewport" content="width=device-width, initial-scale=1, user-scalable=0">
</head>
<body>
<script type="text/javascript">
var ua = navigator.userAgent.toLowerCase();
var isWeixin = ua.indexOf('micromessenger') != -1;
var isAndroid = ua.indexOf('android') != -1;
var isIos = (ua.indexOf('iphone') != -1) || (ua.indexOf('ipad') != -1);
if (!isWeixin) {
document.head.innerHTML = '<link rel="stylesheet" type="text/css" href="<a href=" https:="" res.wx.qq.com="" open="" libs="" weui="" 0.4.1="" weui.css"="">https://res.wx.qq.com/open/libs/weui/0.4.1/weui.css">';
document.body.innerHTML = '<div class="weui_msg"><div class="weui_icon_area"><i class="weui_icon_info weui_icon_msg"></i></div><div class="weui_text_area"><h4 class="weui_msg_title">请在微信客户端打开链接</h4></div></div>';
}
</script>
</body>
</html>
网友回复
明显后台逻辑的问题，被跳转是因为后台设定了没有登录状态时跑去公众号进行授权。
你们业务流程没理清楚。
问题如图额